Center for Astrophysical Research in Antarctica
This is meant to be given to the students.
For example, it takes 0.12 second for light (or microwaves, or any other kind of electromagnetic radiation) to travel from the Earth to a communications satellite in a geosynchronous orbit. The round trip - from Earth and back - for a microwave transmission would be twice this, or 2 x 0.12 second = 0.24 second, which explains why there is a slight delay in some long-distance telephone calls. We can think of this as a distance of 0.24 light-seconds.
Light takes 1.28 seconds to travel from the Moon to Earth, and 500 seconds or 8.3 minutes to travel from the Sun to Earth. Since Jupiter is 5.2 times as far from the Sun as the Earth, it takes 5.2 x 8.3 min = 43 min for light to travel from the Sun to Jupiter, and we can say that Jupiter is 43 light-minutes from the Sun. Pluto is 39.5 times farther from the Sun than is the Earth; this works out to a distance of 5.5 light hours.
These examples give you another way of thinking about the size of the Solar System. (As still another example, stars are typically light years apart, not light hours.)
Astronomers thus use time to measure distances, and the scale is based on the speed of light. This is possible because of an important rule:
The other important rule is:
distance traveled
speed = -------------------------------.
time to travel that distance
We'll first practice using this equation by calculating the speed
of a ball thrown by one student to another. We need to measure the
distance between the students, and we need to measure the time-of-
flight. If the distance between the students is measured in
feet, and the time-of-flight is measured in seconds,
then we will measure the speed in feet per second.
To understand why this last statement is true, we need to understand a bit about how a TV set works. A beam of electrons hits a phosphor inside the TV tube, creating a glowing dot. The electron beam is scanned rapidly sideways and down the screen, such that in just 1/30th of a second, the whole screen has been "painted" by 525 scans of the glowing dot, from top to bottom. The scanning is too fast for the eye to see. In the next 1/30th of a second, another picture is painted, and so on, to create something the eye + brain interprets as a moving image.
Since there are 525 scans (also called "lines" or "scan lines"), each one must take only
1 1 -------- = -------- 30 x 525 15,750of a second to travel from the left-hand side of the screen to the right-hand side of the screen.
That means that if a reflected image is offset to the right by one-tenth of the width of the screen, the difference in time between the main image and the ghost must be 157,500th of a second; if the offset is only 1% of the width of the screen, then the difference in time is 1,575,000th of a second, and so on. The point is that a measurement of the offset of the ghost, as a fraction of the width of the screen, gives us a way to measure very small intervals of time.
Our antenna, the large dome, and Rockford, Illinois are approximately in a line. That means that if we tune to stations in Rockford, the difference in distance traveled between the main signal and the reflected signal will be simple to calculate - it is just twice the distance from our antenna to the main building. The Rockford stations are:
__________ offset distance between main image and ghost image
Measure the width of the TV screen in millimeters, and write down that number in the space below.
__________ width of the TV screen
Now, what fraction of the width of the screen is the offset of the ghost image?
offset distance ------------------- = ----------------- = width of TV screenThis is equal to the fraction of the width of the screen
Now, finally, what is the delay time for the ghost? That is, by what amount of time did the ghost signal arrive after the main signal?
__________ seconds delay.
__________ distance between the antenna and the main building
Now write down the
__________ difference in distance traveled from Rockford to the antenna between the main signal and the reflected signal
_____________ speed of light.
How can you check whether this number is right?
[Hint: the number you wrote down above is probably in feet per second or in meters per second. The number for the speed of light you will find in a textbook is probably in miles per second or in kilometers per second. That means that you will need to do a bit more math in order to compare the two values.]
Important Disclaimers and Caveats:
Questions? Comments? email us at caraweb@astro.uchicago.edu Last modified Thursday, 23-Jul-1998 17:35:07 CDT